a train travelling at a uniform speed for 360 km would have taken 48 minutes less to travel the same distance if its speed 5 kilometre per hour more find the original speed of the train
Answers & Comments
sagarika
Let the original speed of he train be x km/hr. Time taken at original speed= 360/x hrs Time taken at increased speed= 360/x+5 hrs Now, 360/x - 360/x+5 = 48/60
=> 360[1/x - 1/x+5] =4/5 => x²+5x-2250=0 => x=45 or -50 (as speed cannot be negative) =>x=45 km/hr.
Answers & Comments
Time taken at original speed= 360/x hrs
Time taken at increased speed= 360/x+5 hrs
Now,
360/x - 360/x+5 = 48/60
=> 360[1/x - 1/x+5] =4/5
=> x²+5x-2250=0
=> x=45 or -50 (as speed cannot be negative)
=>x=45 km/hr.
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