Answer:
The volume of the toy is 231 cm cube.
Total surface area of the toy is 203.5 cm
square.
Step-by-step explanation:
Given: A toy is in the form of cone mounted on the hemisphere of diameter 7 cm. the total height of the tower is 14.5 cm.
To find: The volume and total surface
area of the toy?
Solution:
Hemisphere of diameter 7 cm
Radius is 7 = -3.5 Height of the oy = 14.5
Height of the cone 14.5-3.5-11cm
Height of the hemisphere-3.5cm
According to question,
Volume of the toy = V(cone)+ V(hemisphere)
V = 1/3 * pi * r ^ 2 * h + 4/3 * pi * r ^ 3
V = 1/2 * pi * r ^ 2 * ([h + 2r])
V = 1/2 * 27/7 * (3.5) ^ 2 / 11 + 2(3.5)
V=××3.5×3.5×18
V = 231
l = sqrt(r ^ 2 + h ^ 2)
l = sqrt(3.5 ^ 2 + 11 ^ 2)
1 = sqrt(133.25)
1-11.5
Total surface of the toy = TSA(cone)+ TSA(hemisphere)
TSA=²+2r²
TSA-3.5(11.5+2(3.5)) TSA=×3.5× 18.5
TSA=203.5em²
Total surface area of the toy is 203.5 cm square.
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Answers & Comments
Answer:
The volume of the toy is 231 cm cube.
Total surface area of the toy is 203.5 cm
square.
Step-by-step explanation:
Given: A toy is in the form of cone mounted on the hemisphere of diameter 7 cm. the total height of the tower is 14.5 cm.
To find: The volume and total surface
area of the toy?
Solution:
Hemisphere of diameter 7 cm
Radius is 7 = -3.5 Height of the oy = 14.5
Height of the cone 14.5-3.5-11cm
Height of the hemisphere-3.5cm
According to question,
Volume of the toy = V(cone)+ V(hemisphere)
V = 1/3 * pi * r ^ 2 * h + 4/3 * pi * r ^ 3
V = 1/2 * pi * r ^ 2 * ([h + 2r])
V = 1/2 * 27/7 * (3.5) ^ 2 / 11 + 2(3.5)
V=××3.5×3.5×18
V = 231
The volume of the toy is 231 cm cube.
l = sqrt(r ^ 2 + h ^ 2)
l = sqrt(3.5 ^ 2 + 11 ^ 2)
1 = sqrt(133.25)
1-11.5
Total surface of the toy = TSA(cone)+ TSA(hemisphere)
TSA=²+2r²
TSA-3.5(11.5+2(3.5)) TSA=×3.5× 18.5
TSA=203.5em²
Total surface area of the toy is 203.5 cm square.
Step-by-step explanation:
please mark me as brainlist dude..✌️
[tex]Volume \: of \: cone + Volume \: of \: hemisphere = \frac{1}{3} \pi \: r {}^{2} h + \frac{2}{3} \pi \: r {}^{3} . \\ = \frac{1}{3} \times \frac{22}{7} \times (3.5) {}^{2} \times 14.5 + \frac{2}{3} \times \frac{22}{7} \times (3.5) {}^{3} . \\ = \frac{22}{21} \times 12.25 \times 14.5 + \frac{44}{21} \times 42.875. \\ = \frac{22}{21} \times 177.625 + \frac{44}{21} \times 42.875. \\ = \frac{22 + 44}{21} \times 177.625 \times 42.875. \\ = 3.14 \times 177.625 \times 42.875. \\ = 23,913.20cm {}^{3} .[/tex]