A tank (not rigid) contains 2.3 L of helium gas at 25°c. What will be the volume of the tank after healing it and its content to 40°c temperature at constant pressure?
A tank (not rigid) contains 2.3 L of helium gas at 25°c. What will be the volume of the tank after healing it and its content to 40°c temperature at constant pressure?
Note:
Convert degree celsius to kelvin when solving gas laws problem.
kelvin = degree celsius + 273.15
Kelvin = 25°c + 273.15 = 298.15 K
Kelvin = 40°c + 273.15 = 313.15 K
Given:
V1 (initital volume) = 2.3 L
T1 (initial temperature) = 25°c or 298.15 K
V2 (final volume) = unknown ?
T2 (final temperature) = 40°c or 313.15 K
Solution:
We can solve this problem using Charles' law which states that, volume is directly proportional to kelvin temperature when the amount and pressure of the gas are constant. Formula is V1/T1 = V2/T2 and to solve for V2, we can use V2 = V1T2 / T1.
V2 = V1T2 / T1
= 2.3 L × 313.15 K / 298.15 K (cancel unit kelvin)
Answers & Comments
Verified answer
Good Day..
Problem:
A tank (not rigid) contains 2.3 L of helium gas at 25°c. What will be the volume of the tank after healing it and its content to 40°c temperature at constant pressure?
Note:
Convert degree celsius to kelvin when solving gas laws problem.
kelvin = degree celsius + 273.15
Kelvin = 25°c + 273.15 = 298.15 K
Kelvin = 40°c + 273.15 = 313.15 K
Given:
V1 (initital volume) = 2.3 L
T1 (initial temperature) = 25°c or 298.15 K
V2 (final volume) = unknown ?
T2 (final temperature) = 40°c or 313.15 K
Solution:
We can solve this problem using Charles' law which states that, volume is directly proportional to kelvin temperature when the amount and pressure of the gas are constant. Formula is V1/T1 = V2/T2 and to solve for V2, we can use V2 = V1T2 / T1.
V2 = V1T2 / T1
= 2.3 L × 313.15 K / 298.15 K (cancel unit kelvin)
= 720.245 L / 298.15
= 2.416 L
Answer:
The volume is 2.416 L
Hope it helps..=)