Let principal be ₹P
Let Rate of Interest be R% per annum.
So,
➡ Interest for 1 year = PR × 1/100
➡ Amount = P + PR/100 = ₹2200 ..... (i)
➡ Interest for 4 years = 4PR/100
➡ Amount = P + 4PR/100 = ₹2800 .......(ii)
Subtracting (i) from (ii), we get,
➡ 3PR/100 = 600
➡ PR = 600 × 100/3
➡ PR = 20000
Putting the value of PR in (i), we get,
➡ P + 20000/100 = 2200
➡ P + 200 = 2200
➡ P = ₹2000
➡ R = 20000/2000
➡ R = 10% per annum.
Hence,
★ Principal Amount = ₹2000
★ Rate of Interest = 10% p.a.
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Let principal be ₹P
Let Rate of Interest be R% per annum.
So,
➡ Interest for 1 year = PR × 1/100
➡ Amount = P + PR/100 = ₹2200 ..... (i)
➡ Interest for 4 years = 4PR/100
➡ Amount = P + 4PR/100 = ₹2800 .......(ii)
Subtracting (i) from (ii), we get,
➡ 3PR/100 = 600
➡ PR = 600 × 100/3
➡ PR = 20000
Putting the value of PR in (i), we get,
➡ P + 20000/100 = 2200
➡ P + 200 = 2200
➡ P = ₹2000
➡ R = 20000/2000
➡ R = 10% per annum.
Hence,
★ Principal Amount = ₹2000
★ Rate of Interest = 10% p.a.
Answer: