[tex] \huge{ \purple{ \textbf{Aɳรωε૨}}}[/tex]

The amount of principle money is 2000 rupees and the rate of interest is 10%.

Step-by-Step explanation:

Let the principle amount of money is x rupees and rate of interest is y%.

then, the interest after one year is (x×y) /100 rupees.

then , xy/100 + x =2200

⇒100x + xy = 220000 ->(1)

and, the interest after 4 years is 4xy/100 rupees.

then, x+4xy/100 =280000->(2)

Calculating (2)-(1) we get,

3xy=60000

⇒xy=20000

then, (1) ⇒100x+xy=220000

⇒100x+20000=220000

⇒100x = 200000

x=2000 rupees

Therefore,xy=20000⇒2000y=20000⇒y= 10

Verified answer

[tex]∴ Interst \: paid \: in \: 3 \: years  \: \\ \\ =2,800-2,200 \\ \\ = 600[/tex]

[tex] \: \: \: Annual \: Interest \\ \\ = \frac{600}{3} \\ \\ = 200[/tex]

[tex]Sum \: lent \: at \: the \: begining \\ \\ = 2,200 -( 200 \times 1) \\ \\ = 2,200 - 200 \\ \\ = 2,000[/tex]

[tex]Rate \: of \: simple \: Interest \\ \\ = \frac{200}{2,000} \times 100 \\ \\ = \frac{20,000}{2,000} \\ \\ = 10 \: \%[/tex]