Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−x
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=500
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=500
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400x=80
Let the number of 5 rupee notes be x,thenThe number of 10 rupee notes =90−xThen ,according to the question5x+10(90−x)=5005x+900−10x=5005x=400x=80There are 80 notes of Rs.5 and 10 notes of Rs.10.
Answers & Comments
Step-by-step explanation:
Verified answer
Answer:
Number of ₹5 notes = 80
Number of ₹10 notes = 10
Step-by-step explanation:
Forming algebraic expression and solving:
Let the number of ₹5 notes = x
The number of ₹10 notes = y
Total number of notes = 90
⇒ x + y = 90 ------------------(I)
x = 90 - y ---------------(II)
Value of 5 notes = 5*x = 5x
Value of 10 notes = 10*y = 10y
Total amount = ₹500
⇒ 5x + 10y = 500 -------------(III)
Divide the entire equation by 5,
⇒ x + 2y = 100 --------------(Iv)
Substitute x = 90 - y in equation (IV),
90 - y + 2y = 100
90 + y = 100
Subtract 90 from both sides,
y = 100 - 90
[tex]\s \boxed{y =10 }[/tex]
Substitute y = 10 in equation (II)
x = 90 -10
[tex]\sf \boxed{x = 80}[/tex]