Given:

A student did six of ten problems correctly.

To find:

The ratio of the number of right problems to the number of wrong problems.

Also, for every two wrong answers, the number of correct answers.

Solution:

(i)

As given,

The total number of problems = 10

The number of problems the student did correctly = 6

So, the number of problems the student did incorrectly = 10 - 6 = 4

Hence,

The ratio of correct problems to the incorrect problems is

= \frac{correct \: problems}{incorrect \: problems}=

incorrectproblems

correctproblems

= \frac{6}{4}=

4

6

= \frac{3}{2}=

2

3

Hence, the ratio of the number of right problems to the number of wrong problems is 3:2.

(ii)

Now,

the ratio of the number of right problems to the number of wrong problems i.e. 3:2 represents that for every three problems student did correct, the two problems were incorrect.

Thus,

For every two incorrect problems, the student did three problems correctly.