a student recorded the weight of dry raisins as 5.4g and on soaking them for 4-5 hrs the weight was 7.6g.calculate the percentage of water imbibed by the raisins
Dry weight of raisins = 5.4g weight weight of raisins = 7.6g weight of water imbibed,
% of water imbibed =
Hence, Percentage of water imbibed is 40.74%
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sakshi307
Weight of dry raisins=5.4g weight of raisins after soaking them=7.6g % of water imbided by raisins=(weight of wet raisins-weight of dry raisins÷weight of dry raisins)×100
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Dry weight of raisinsweight weight of raisins
weight of water imbibed,
% of water imbibed =
Hence, Percentage of water imbibed is 40.74%
weight of raisins after soaking them=7.6g
% of water imbided by raisins=(weight of wet raisins-weight of dry raisins÷weight of dry raisins)×100