A straight wire of mass 200g and length 1.5m carries a current of 2A. It is suspended in mid air by a uniform horizontal magnetic field B.A straight wire of mass 200g and length 1.5m carries a current of 2A. It is suspended in mid air by a uniform horizontal magnetic field B.
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Answer:
Solution:
Magnetic force on straight wire
F= Bil sinθ= Bil sin90
∘
= Bil
For equilibrium of wire in mid-air,
F=mg
Bil=mg
∴B=
il
mg
=
2×1.5
200×10
−3
×9.8
=0.65T