Answer:
19.6m/s
Explanation:
we know that v²=u²+2as
here, we know,u=0m/s, a=g=9.8m/s², s=19.6m
then v²=0+2×9.8×19.6
or, v= 19.6m/s(ans)
as the stone is "released" it's initial velocity is zero. When the initial velocity is zero then its the case of a freely falling body. For a freely falling body velocity at height h from release point is √2gh. So V=√(2*9.8*19.6). V=√(19.6*19.6).
V=19.6m/s
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Verified answer
Answer:
19.6m/s
Explanation:
we know that v²=u²+2as
here, we know,u=0m/s, a=g=9.8m/s², s=19.6m
then v²=0+2×9.8×19.6
or, v= 19.6m/s(ans)
Answer:
19.6m/s
Explanation:
as the stone is "released" it's initial velocity is zero. When the initial velocity is zero then its the case of a freely falling body. For a freely falling body velocity at height h from release point is √2gh. So V=√(2*9.8*19.6). V=√(19.6*19.6).
V=19.6m/s