Answer:

Given that

Initial velocity

u = 0

Tower height = total distance = 19.6m

g = 9.8 m/s2

Find out

Final velocity just before touching the ground.

Solution

Let us solve using third equation of motion

v2 = u2 + 2gs

v2 = 0 + 2 × 9.8 × 19.6

v2 = 384.16

v = √(384.16)

v = 19.6m/s

Answer

Final velocity just before touching the ground = v = 19.6m/s

Verified answer

Answer:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v² = u²+ 2gs

v²= 0+2×9.8×19.6

v²= 384.16

v = 19.6m/s