A stone is dropped from top of roof of height 14m . find the time taken by the stone to reach the ground and the velocity of stone before touching the ground . Ye bata dijiye
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Explanation:
Solution
Solutionverified
SolutionverifiedVerified by Toppr
SolutionverifiedVerified by TopprInitial Velocity u=0
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6m
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motion
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gs
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2 =384.16
SolutionverifiedVerified by TopprInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2 =384.16⇒v=19.6m/s
Answer:
Initial Velocity u=0
Fianl velocity v=?
Height, s=19.6m
By third equation of motion
v
2
=u
2
+2gs
v
2
=0+2×9.8×19.6
v
2
=384.16
⇒v=19.6m/s