a squirrwl sits at the top of a 14 foot tall tree. he spies a nut pn the ground at some distance away and his line of sight makes a 74 degree with the tree. how far is the nut from the squirel?
pasagot po plss.
pasagot po plss.
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Answer:
160.45
Step-by-step explanation:
use trigonometry
Given:
degree=74
adj=14
opp=?
hypo=?
To get the distance from the tree to the nut :
tan74°= opp/14
opp= tan74°(14)
opp= 48.8
Distance between the squirrel to the nut:
use the Pythagorean theorem:
c^2=a^2+b^2
c^2= 48.8^2+ 14^2
c^2= 2381.4 +196
c=√2577.4
c= 160.45
hope it can help