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ayushi00013
@ayushi00013
August 2021
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a square whose sides are 2 cm,have got its corners cut.a regular octagon is formed find the length of each side
Answers & Comments
AritroRoy
Each side is 16cm.
Hope this will help.
1 votes
Thanks 0
ayushi00013
i want steps
TheUrvashi
Let ABCd is a square and AB = BC = CD= DA = 2 m
Again, we form a rectangular octagon by cutting all four corners.
Let EF = FG = GH = HI = IJ = JK = KL = LE = x
Now, by symmetry, we get
AE = Al = BG = BF = Ch = CI = DJ = Dk = a
In triangle ALE, apply Pythagorus theorem,
AL2 = AE2 + LE2
=> x2 = a2 + a2
=> x2 = 2a2
=> x = a√2
=> a = x/√2 ....................1
Again, AB = AE + EF + FB
=> 2 = a + x + a
=> 2 = 2a + x
=> 2 = 2x/√2 + x
=> √2x + x = 2
=> (√2 + 1)x = 2
=> x = 2/(√2 + 1)
So, the side of an octagon is 2/(√2 + 1) m
2 votes
Thanks 7
RajendraBhukar
I see your answer nice answer you are writing in maths that is too good
TheUrvashi
thanx
RajendraBhukar
I think that you are old in this app
TheUrvashi
no i am using since February 2018
ayushi00013
can u send me the diagram too
RajendraBhukar
I am also old
RajendraBhukar
what happened
RajendraBhukar
why are you not replying me
RajendraBhukar
what happened to you
RajendraBhukar
kuch to bol
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Answers & Comments
Hope this will help.
Again, we form a rectangular octagon by cutting all four corners.
Let EF = FG = GH = HI = IJ = JK = KL = LE = x
Now, by symmetry, we get
AE = Al = BG = BF = Ch = CI = DJ = Dk = a
In triangle ALE, apply Pythagorus theorem,
AL2 = AE2 + LE2
=> x2 = a2 + a2
=> x2 = 2a2
=> x = a√2
=> a = x/√2 ....................1
Again, AB = AE + EF + FB
=> 2 = a + x + a
=> 2 = 2a + x
=> 2 = 2x/√2 + x
=> √2x + x = 2
=> (√2 + 1)x = 2
=> x = 2/(√2 + 1)
So, the side of an octagon is 2/(√2 + 1) m