hey don't try to fool us I know your qs is wrong as whatever cas br concave never forms image between focus and pole .
real image not possible.
Explanation:
Given v = -20 cm. f = -25 cm. u = ?
Sign convention is that distances measured (from the pole of the mirror) against the direction of the rays from the object are negative.
1/f = 1/u + 1/v
1/u = 1/f - 1/v = -1/25 + 1/20 = 1//100.
But in concave mirror the object distance is negative as per the sign convention.
So the formation of real image at a distance 20 cm due to a concave mirror of focal length 25 cm isn't possible.
For a concave mirror, real image distance cannot be less than the focal length.
In a convex mirror all the images are virtual only.
Problem with the given data.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
hey don't try to fool us I know your qs is wrong as whatever cas br concave never forms image between focus and pole .
real image not possible.
Explanation:
Given v = -20 cm. f = -25 cm. u = ?
Sign convention is that distances measured (from the pole of the mirror) against the direction of the rays from the object are negative.
1/f = 1/u + 1/v
1/u = 1/f - 1/v = -1/25 + 1/20 = 1//100.
But in concave mirror the object distance is negative as per the sign convention.
So the formation of real image at a distance 20 cm due to a concave mirror of focal length 25 cm isn't possible.
For a concave mirror, real image distance cannot be less than the focal length.
In a convex mirror all the images are virtual only.
Problem with the given data.