Answer:
To find the image distance we can use the mirror formula:
1/f = 1/v - 1/u
where:
f = focal length of the mirror
v = image distance
u = object distance
Given:
f = 2.5 cm
u = -5 cm (negative sign indicates that the object is in front of the mirror)
Plugging the values into the formula we can solve for v:
1/2.5 = 1/v - 1/-5
To simplify the equation let's find the common denominator:
1/2.5 = (1/v) + (1/5)
Multiplying both sides by 2.5v:
v = 2.5 + 0.5v
Simplifying the equation:
0.5v = 2.5
v = 2.5 / 0.5
v = 5 cm
Therefore the image distance is 5 cm.
Explanation:
u=-5 cm, f=10 cm
We know that
v
1
+
u
=
f
⇒
(−5)
10
20
5
3
∴v=
cm=3.33cm
The position of the image is 3.33 cm behind the convex mirror.
Magnification, m=−
=−
−5
3.33
=0.66
The image is virtual and erect.
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Verified answer
Answer:
To find the image distance we can use the mirror formula:
1/f = 1/v - 1/u
where:
f = focal length of the mirror
v = image distance
u = object distance
Given:
f = 2.5 cm
u = -5 cm (negative sign indicates that the object is in front of the mirror)
Plugging the values into the formula we can solve for v:
1/2.5 = 1/v - 1/-5
To simplify the equation let's find the common denominator:
1/2.5 = (1/v) + (1/5)
Multiplying both sides by 2.5v:
v = 2.5 + 0.5v
Simplifying the equation:
0.5v = 2.5
v = 2.5 / 0.5
v = 5 cm
Therefore the image distance is 5 cm.
Explanation:
u=-5 cm, f=10 cm
We know that
v
1
+
u
1
=
f
1
⇒
v
1
+
(−5)
1
=
10
1
⇒
v
1
=
20
1
+
5
1
=
10
3
∴v=
3
10
cm=3.33cm
The position of the image is 3.33 cm behind the convex mirror.
Magnification, m=−
u
v
=−
−5
3.33
=0.66
The image is virtual and erect.