A source supplies heat to a system at the rate of 1000 W. If the system performs work at a rate of 200 W. The rate at which internal energy of the system increase is
(1) 500 W (2) 600 W (3) 800 W (4) 1200 W
(1) 500 W (2) 600 W (3) 800 W (4) 1200 W
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The rate at which the internal energy of the system increases is equal to the difference between the heat supplied and the work done.
So, the rate at which the internal energy of the system increases is given by: 1000 W - 200W = 800 W.
Therefore, the rate at which the internal energy of the system increases is 800 W.
Answer: (3) 800 W.
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