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Answer:

To calculate the number of photons emitted in one second, we can use the formula:

Explanation:

Number of photons = Energy emitted / Energy of one photon

Given that the energy emitted is 1 Joule and the wavelength is 3000 Å (Angstroms), we need to convert the wavelength to meters and use the energy-wavelength relationship:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

First, we convert the wavelength from Angstroms to meters:

3000 Å = 3000 × 10^(-10) m (1 Å = 10^(-10) m)

Now, we can calculate the frequency (ν) using the speed of light (c):

c ≈ 3 × 10^8 m/s (approximate value of the speed of light)

Using the equation c = λν, we can rearrange it to solve for the frequency:

ν = c / λ

ν = (3 × 10^8 m/s) / (3000 × 10^(-10) m)

ν = 10^18 Hz

Now, we can calculate the energy of one photon using Planck's equation:

Energy of one photon = Planck's constant (h) × frequency (ν)

h ≈ 6.626 × 10^(-34) J·s (Planck's constant)

Energy of one photon = (6.626 × 10^(-34) J·s) × (10^18 Hz)

Energy of one photon = 6.626 × 10^(-16) J

Finally, we can calculate the number of photons using the formula:

Number of photons = Energy emitted / Energy of one photon

Number of photons = 1 J / (6.626 × 10^(-16) J)

Number of photons ≈ 1.512 × 10^15 photons

Therefore, the number of photons emitted in one second is approximately 1.512 × 10^15 photons.