A. Solve the value of x. What are the dimensions of the field?
B. What is the length of the wire required to put around the field to
complete its boundary?
C. How much area is required to be irrigated in his field?
Pahelp po plsss
B. What is the length of the wire required to put around the field to
complete its boundary?
C. How much area is required to be irrigated in his field?
Pahelp po plsss
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Answer:
A. x=8
B. 136m
c. 832 m²
Step-by-step explanation:
The figure is a rectangle
Rectangle has 4 right triangles.
Rectangle has 2 equal parallel sides
A. any of the given may do.
in width
2x = x+ 8
x= 8
in length
7x-4 = 6x+4
x=8
B. Perimeter = 2L + 2W = 2 (L+W)
L = 7(8)-4=52m
W = 2(8) = 16m
total length of wire is the Perimeter of entire lot
P = 2(52+16) = 136m
C. Area = LW
A = (52)(16) = 832m²
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