a solution is prepared by dissolving a certain amount of solute in 400 g of wate...

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September 2022 1 0 Report

a solution is prepared by dissolving a certain amount of solute in 400 g of water the percentage by mass of the solute in the solution is 7.50 8% calculate the mass of solute

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bryantjarlath

Answer:

Correct option is
Correct option isC
Correct option isC12.19 g
Correct option isC12.19 gWeight percentage=[
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solvent
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38=
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x=
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x= 97.62
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x= 97.621190
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x= 97.621190
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x= 97.621190 =12.190g
Correct option isC12.19 gWeight percentage=[ Weight of solute+ weight of solventWeight of solute ]×100 Let the weight of the solute be 'x'.2.38= x+500x×100 ⟹2.38x+1190=100x⟹1190=97.62x⟹x= 97.621190 =12.190g∴ Mass of solute =12.19 grams