Step-by-step explanation:

length = 1m = 100cm

width = 10cm

height = 6 cm

Then volume of the bar = length x breadth x height

[tex] = (100 \times 10 \times 6) {cm}^{3} \\ \\ = 6000 {cm}^{3} [/tex]

Now,

1 cm³ of iron weighs 8 gm

then,

6000 cm³ of iron would weigh

= (6000 × 8) gm

=

[tex]48000 \: gm[/tex]