[tex]\Huge\mathbb{ANSWER:}[/tex]

The snail climbs 5 meters daily but slides back 4 meters every evening, which means it makes a net progress of 1 meter each day (5 meters climbed - 4 meters slid back).

To calculate how many days it will take for the snail to escape the 20-meter deep pit, we need to divide the total distance (20 meters) by the net progress made each day (1 meter).

• 20 meters / 1 meter = 20 days

Therefore, it will take the snail approximately 20 days to escape the hole.

PROBLEM SOLVING

To find how long will it take for a snail to escape the hole, we'll use the formula:

[tex]\large\qquad\boxed{\rm{\:\:Time = \dfrac{Distance}{Speed}\:\:}}[/tex]

where:

• Distance is the total distance to be covered.
• Speed is the average speed of the snail in covering that distance.

The snail climbs 5 meters every day but slides back 4 meters every evening, so its net upward progress each day is:

[tex]\qquad\large\boxed{\rm{\:\:5 - 4 = \red{1 \: meter}\:\:}}[/tex]

So the snail covers 1 meter per day. To climb out of the 20-meter deep pit, it needs to cover a distance of 20 meters. So:

• Distance = 20 meters
• Speed = 1 meter per day

Substitute the given values into the formula:

[tex]\quad\large\rm{Time = \dfrac{20\: meters}{1\: meter\: per\: day}}[/tex]

[tex]\qquad\large\boxed{\boxed{\rm{\:\:Time = 20\: days\:\:}}}[/tex]

Therefore, the snail will take 20 days to escape the hole.