A sign board is in the shape of an isosceles triangle. The third side measures 3 feet less than twice the length of each side. Find the length of the sides of the sign board if the perimeter is 61 feet.
A sign board is in the shape of an isosceles triangle. The third side measures 3 feet less than twice the length of the other two sides. Find the length of the sides of the sign board if the perimeter is 61 feet.
✎ Answerandexplanation:
Let
x be the length of the first and second sides since the triangle is isosceles, and
2x-3be the length of the third side.
Since the perimeter is equal to 61 ft, we can make an equation to solve for x:
(2x-3)+x+x=61
4x-3=61
4x=64
∴x=16ft<lengthofthefirstandsecondsides>
The length of the first and second sides are x=16ft. Now we have to solve for the third side:
2x-3
2(16)-3
32-3→29ft<length of the third side>
✔︎ Let's see if these values add up to the perimeter of the triangle, which is 61 ft.
Answers & Comments
✎ Problem:
A sign board is in the shape of an isosceles triangle. The third side measures 3 feet less than twice the length of the other two sides. Find the length of the sides of the sign board if the perimeter is 61 feet.
✎ Answer and explanation:
Let
Since the perimeter is equal to 61 ft, we can make an equation to solve for x:
The length of the first and second sides are x = 16 ft. Now we have to solve for the third side:
✔︎ Let's see if these values add up to the perimeter of the triangle, which is 61 ft.
Hope This Helps
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