A shopkeeper buys some pens at ₹8 per pen and the same number of pencils at ₹6 per pencil. He makes a 10% profit on the pens and a 20% profit on the pencils. At the end of day, all the pens and pencils are sold out and he makes a profit of ₹320. Find the number of pens purchased.
Answers & Comments
Answer:
Letthenumberofpensbexand
numberofpencilsbey
then
x+y=16ory=16−x
andtheirvalue
8x+1.5y=50
8x+(
2
3
)(16−x)=50
8x+24−(
2
3
)x=50
8x−(
2
3
)x=50−24
(
2
13x
)=26∴x=4
theny=16−x=16−4=12
Answer:
160 pens
Step-by-step explanation:
Let number of pens be x and number of pencils be x
Cost of 1 pen = Rs 8
Cost of x pens = Rs 8x
Profit of x pens = 10% of 8x = [tex]\frac{10}{100}[/tex] × 8x = [tex]\frac{4x}{5}[/tex]
Cost of 1 pencil = Rs 6
Cost of x pencils = Rs 6x
Profit of x pencils = 20 % of 6x = 20/100 × 6x = 6x/5
Total profit = Rs 320
4x/5 + 6x/5 = 320
10x/5 = 320
2x = 320
x = 160
Therefore, the shopkeeper purchased 160 pens.
Hope it helped.