A sequence of all multiples of 3 ending with digit 2 are written in
strictly ascending order as follows:
12, 42, 72, 102, 132, 162, · · ·
What is the 68th term of this sequence? .
strictly ascending order as follows:
12, 42, 72, 102, 132, 162, · · ·
What is the 68th term of this sequence? .
Answers & Comments
Answer:
2022
Step-by-step explanation:
a=12. d=30 n=68
an=a+(n-1)d
=12+(68-1)30
=12+67×30
=12+2010
=2022