A seconds' pendulum is taken to a place where acceleration due to gravity falls to one-fourth. How is the time period of the pendulum affected, if at all? Give reason. What will be its new time period ?
Solution. Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.
Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.
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Explanation:
Solution. Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.
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Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.