A school has a hall which is 22m long and 15.5 m broad . a carpet is laid inside the hall leaving all around the margin of 75 cm from the walls . find the area of carpet and the area of strip left uncoverd if the width of the carpet is 82 cm ,find its cost at the rate of rupees 60 per m.
Answers & Comments
Step-by-step explanation:
In rectangular hall,
Length
(
L
)
=
22
m
Breadth
(
B
)
=
15.5
m
The area of the hall
=
L
×
B
=
22
m
×
15.5
m
=
341
m
2
Margin of carpet
=
75
c
m
=
75
×
1
100
m
=
0.75
m
[Since,
1
c
m
=
1
100
]
In carpet,
Length
(
l
)
=
22
m
−
2
×
0.75
m
=
22
m
−
1.5
m
=
20.5
m
Breadth
(
b
)
=
15.5
m
−
2
×
0.75
m
=
15.5
m
−
1.5
m
=
14
m
Area of the carpet
=
l
×
b
=
20.5
m
×
14
m
=
287
m
2
Area of uncovered portion
=
341
m
2
−
287
m
2
=
54
m
2
Now, it is given that width of the carpet
=
82
c
m
=
82
×
1
100
m
=
0.82
m
Since, Area of the carpet
=
287
m
2
⇒
l
×
b
=
287
m
2
⇒
l
×
0.82
m
=
287
m
2
⇒
l
=
287
m
2
0.82
m
⇒
l
=
287
×
100
82
m
⇒
l
=
350
m
Cost of the carpet per meter
=
R
s
.
60
Cost of fencing the strip
=
350
×
R
s
.
60
=
R
s
.21000