A satelite dish, shaped like a paraboloid, has a width of 9 ft across and a depth of 2 ft. above the vertex. If the receiver is placed at the focus, how high above the venter is the receiver? with solution
Answer: A satellite dish shaped like a paraboloid had 2.4 ft and depth 0.9 ft the receiver placed at the all focus. How far should the receiver be from the vertex?Setting the vertex at (0, 0) and assuming the diameter is 2.4 feet:y = a*x^2 ; 0.9 = a*(1.2)^2 ; a =0.9 / 1.44 = 5/8x^2 = 4*p*y ; 1.44 = p*3.6 ; p = 2/5 = 0.4 feet.Place receiver 0.4 feet above vertex.
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Answer: A satellite dish shaped like a paraboloid had 2.4 ft and depth 0.9 ft the receiver placed at the all focus. How far should the receiver be from the vertex?Setting the vertex at (0, 0) and assuming the diameter is 2.4 feet:y = a*x^2 ; 0.9 = a*(1.2)^2 ; a =0.9 / 1.44 = 5/8x^2 = 4*p*y ; 1.44 = p*3.6 ; p = 2/5 = 0.4 feet.Place receiver 0.4 feet above vertex.
Step-by-step explanation: I answered it in Math.