Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} P_1 & = \text{0.97 atm} \\ T_1 & = 21^{\circ}\text{C} = \text{294 K} \\ T_2 & = -68^{\circ}\text{C} = \text{205 K} \end{aligned}[/tex]
Step 2: Calculate the final pressure by using Gay-Lussac's law.
[tex]\begin{aligned} P_2 & = \frac{P_1T_2}{T_1} \\ & = \frac{(\text{0.97 atm})(\text{205 K})}{\text{294 K}} \\ & = \boxed{\text{0.68 atm}} \end{aligned}[/tex]
Hence, the pressure of oxygen gas is 0.68 atm.
[tex]\\[/tex]
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SOLUTION:
Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} P_1 & = \text{0.97 atm} \\ T_1 & = 21^{\circ}\text{C} = \text{294 K} \\ T_2 & = -68^{\circ}\text{C} = \text{205 K} \end{aligned}[/tex]
Step 2: Calculate the final pressure by using Gay-Lussac's law.
[tex]\begin{aligned} P_2 & = \frac{P_1T_2}{T_1} \\ & = \frac{(\text{0.97 atm})(\text{205 K})}{\text{294 K}} \\ & = \boxed{\text{0.68 atm}} \end{aligned}[/tex]
Hence, the pressure of oxygen gas is 0.68 atm.
[tex]\\[/tex]
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