Verified answer

SOLUTION:

Step 1: List the given values

[tex]\begin{aligned} & P = \text{4.7 atm} \\ & V = \text{2.3 L} \\ & T = 32^{\circ}\text{C} = \text{305.15 K} \end{aligned}[/tex]

Step 2: Calculate the number of moles of gas using ideal gas equation.

[tex]\begin{aligned} PV & = nRT \\ nRT & = PV \\ \frac{nRT}{RT} & = \frac{PV}{RT} \\ n & = \frac{PV}{\text{RT}} \\ & = \frac{(\text{4.7 atm})(\text{2.3 L})}{\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{305.15 K})} \\ & = \boxed{\text{0.43 mol}} \end{aligned}[/tex]

Hence, the number of moles of gas present is 0.43 mol.

[tex]\\[/tex]

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