Answer:

6.5. 10⁵mL

Explanation:

We can solve this problem by using Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

PV = const.

where

p is the pressure of the gas

V is its volume

We can rewrite the formula as

P₁V₁ = P₂V₂

For the gas in this problem:

P₁ = 0.400atm is the initial pressure

V₁: = 75.0mL is the initial volume

P2 765mmHg = 1.006atm is the final pressure (using the conversion factor latm 760atm) =

Solving for V2, we find the final volume:

V₂ = (0.400) (75.0) 1.006 P2 = 29.8mL

d)

We can solve this part by using again the equation:

Where in this case we have:

P1 = 0.400atm is the initial pressure

V₁ = 75.0mL is the initial volume

P2 = 4.00mmHg is the final pressure

Converting into atmospheres,

P2 4.00mmHg. 1 760mmHg/atm =

0.0053atm

And solving for V2, we find the final volume:

V₂ = = (0.400) (75.0) 0.0056 P2 = 5357mL

and)

As before, we use Boyles' Law:

In this part we have:

P1 = 0.400atm is the initial pressure of the gas

V₁ = gas 75.0mL is the initial volume of the

P2= 3.50.10-²torr

1 torr is equivalent to 1 mmHg, so the conversion factor is the same as before, therefore the final pressure in atmospheres is:

p₂ = 3.50 · 10−²mmHg · 760mmHg/atm P2 1

4.6. 10-5atm

And so, the final volume of the krypton gas is:

V₂ (0.400) (75.0) 4.6.10-5 P2 = 6.5. 105 mL

I hope it helps you

Have a nice day