Given:
Height of the mountain (h) = 150 m
Horizontal distance fallen (d) = 30 m
Acceleration due to gravity (g) = 9.8 m/s^2
Calculating time taken to fall vertically (t):
We can use the equation of motion for vertical motion:
h = (1/2) * g * t^2
Plugging in the values, we get:
150 = (1/2) * 9.8 * t^2
Solving for t, we get:
t^2 = (2 * 150) / 9.8
t^2 ≈ 30.6122449
t ≈ 5.53 seconds (rounded to two decimal places)
Calculating initial horizontal velocity (v_x):
We can use the equation for horizontal distance:
d = v_x * t
30 = v_x * 5.53
Solving for v_x, we get:
v_x ≈ 5.42 m/s (rounded to two decimal places)
Calculating initial vertical velocity (v_y):
v_y = g * t
v_y ≈ 9.8 * 5.53
v_y ≈ 54.39 m/s (rounded to two decimal places)
So, the correct solution is:
Time taken to fall vertically (t) ≈ 5.53 seconds
Initial horizontal velocity (v_x) ≈ 5.42 m/s
Initial vertical velocity (v_y) ≈ 54.39 m/s
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Answers & Comments
Given:
Height of the mountain (h) = 150 m
Horizontal distance fallen (d) = 30 m
Acceleration due to gravity (g) = 9.8 m/s^2
Calculating time taken to fall vertically (t):
We can use the equation of motion for vertical motion:
h = (1/2) * g * t^2
Plugging in the values, we get:
150 = (1/2) * 9.8 * t^2
Solving for t, we get:
t^2 = (2 * 150) / 9.8
t^2 ≈ 30.6122449
t ≈ 5.53 seconds (rounded to two decimal places)
Calculating initial horizontal velocity (v_x):
We can use the equation for horizontal distance:
d = v_x * t
Plugging in the values, we get:
30 = v_x * 5.53
Solving for v_x, we get:
v_x ≈ 5.42 m/s (rounded to two decimal places)
Calculating initial vertical velocity (v_y):
We can use the equation of motion for vertical motion:
v_y = g * t
Plugging in the values, we get:
v_y ≈ 9.8 * 5.53
v_y ≈ 54.39 m/s (rounded to two decimal places)
So, the correct solution is:
Time taken to fall vertically (t) ≈ 5.53 seconds
Initial horizontal velocity (v_x) ≈ 5.42 m/s
Initial vertical velocity (v_y) ≈ 54.39 m/s