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A rectangle has length of 22 m and has width of 10 m.The perimeter of the rectangle is 64.
Solution:
P=2(l+w)=2·(22+10)=64m
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Answer L = 22 m
W = 10
P = 2L + 2W
P = 2(22) + 2(10)
P = 64 m
TIPS: Perimeter is just sum of all sides of figure. So if you forgot formula, you don't actually need it. Just add all the sides like this,
P = 22 + 22 + 10 + 10 = 64 m
Step-by-step explanation:
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Answers & Comments
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A rectangle has length of 22 m and has width of 10 m.The perimeter of the rectangle is 64.
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Solution:
P=2(l+w)=2·(22+10)=64m
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#CarryOnLearning
<( ̄︶ ̄)↗
Answer L = 22 m
W = 10
P = 2L + 2W
P = 2(22) + 2(10)
P = 64 m
TIPS: Perimeter is just sum of all sides of figure. So if you forgot formula, you don't actually need it. Just add all the sides like this,
P = 22 + 22 + 10 + 10 = 64 m
Step-by-step explanation: