A rectangle has length 22 mm and width 12 mm. If its length were increased by 7 percent sign and its width were increased by 6 percent sign, what would be the percentage increase in the rectangle's area?
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Length of rectangle , L = 22mmwidth of rectangle , B = 12mm
so, area of rectangle = L × B = 22 × 12 = 264mm²
now, length was increased by 7 %
so, new length of rectangle = 22 + 7% of 22
= 22 + 154/100 = 22 + 1.54 = 23.54 mm
width was increased by 6 %
so, new width of rectangle = 12 + 6 % of 12
= 12 + 6 × 12/100 = 12.72 mm
so, area of new rectangle = 23.52 × 12.72 mm²
= 299.1744 mm²
change in area = 35.1744 mm²
% change in area = 35.1744/264 × 100 = 13.32 %
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ANSWER :-
13.32 %
EXPLAINATION :-
L = 22mm
B = 12mm
So, area of rectangle = L × B => 22 × 12
=> 264mm²
Now, length was increased by 7 %
So, new length of rectangle = 22 + 154/100
=> 22 + 1.54
=> 23.54 mm
Breadth was increased by 6 %
So,
New width of rectangle = 12 + 6 × 12/100
=> 12.72 mm
So,
Area of new rectangle = 23.52 × 12.72 mm²
= 299.1744 mm²
Change in area = 35.1744 mm²
In % = 35.1744/264 × 100
=> 13.32 %