a rectangle has a width of 2x - 3 m and a length of x + 6 m find the area of the rectangle.pls need kona po now pa answer po ASAP. Created by xMxry. Math

a rectangle has a width of 2x - 3 m and a length of x + 6 m find the area of the...

KAntoineDoix

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$\large\underline{\mathbb{PROBLEM}:}$

A rectangle has a width of 2x - 3 m and a length of x + 6 m find the area of the rectangle.

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$\quad \Large \rm{(2x^2 + 9x - 18) \: sq. \: meters}$

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$\large\underline{\mathbb{SOLUTION}:}$

» The area of the rectangle can be obtained by multiplying the the length and the width.

$Area = length \cdot width$

$Area = (x + 6)(2x - 3)$

» Multiply the two binomials by using the FOIL method.

$Area = 2x^2 - 3x + 12x - 18$

$Area = 2x^2 + 9x - 18$

$\therefore$ The area of the rectangle with the given length and width is 2x² + 9x - 18 sq. meters

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xMxry pero sa iba po nakalagay is 2x²+3x-9 yung answer

xMxry salamat pa din po

Xochitil lamats

XxGreatdanielxX KantoIneDoix

XxGreatdanielxX follow back me

hilarykaitlyn ok

janicefrancisco447

✒️Answer:

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$\huge \boxed {\underline {\tt {{ \blue{(2x^{2} +9x−18) }}}}}$

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✏️Solution

* The Solution Is on The Pic

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