Answer:

Given:

l = 3w - 2

area = 16 sq. units

Find the width (w)

area = lw

we can't take the factor (w+2) since it is negative

The dimensions are

width = 8/3 or 2.67 units

width = 8/3 or 2.67 unitslength = 3(8/3) - 2 = 6 units

Now solve for the perimeter

P = 2l + 2w

= 2(6) + 2(8/3)

= 17.33 units

Answer:

Rectangle dimension: 16 x 8/3

Perimeter: 52/3 or 17 1/3 or 17.33

Step-by-step explanation:

let L be the length

W be the width

A = area = 16

P = perimeter = ?

length is 2 less than 3 times the width:

L = 3W-2

A = LW

16 = W(3W - 2)

16 = 3W² - 2W

3W²-2W-16 = 0

by factoring we get the width (W)

(3W - 8) (W + 2) = 0

3W - 8 = 0

3W = 8

W = 8/3

find L

L = 3W -2

L = 3(8/3) - 2

L = 8 -2

L = 6

solve for Perimeter (P)

P =  2L + 2W

p = 2(6) + 2(8/3)

P =  12 + 16/3

P = (36 + 16)/3

P =  52/3 or 17 1/3 or 17.33

checking:

A = LW

16 = 6(8/3)

16 = 2(8)

16 = 16, OK