Dear user,
Please find below the solution to the asked query:
Given here:
i= 60°
t= 0.1m
n= 1.5
now,
Lateral shift= d=
n = sin i / sin r
sin r = sin 60 / 1.5
sin r = 0.5773
r = 0.5773 = 35.26
d = 0.1 × { sin (60-35.26) / cos 35.2}
= 0.051 m.
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Answer:
Dear user,
Please find below the solution to the asked query:
Given here:
i= 60°
t= 0.1m
n= 1.5
now,
Lateral shift= d=![t \times ( \sin ( i - r )/ cos r) t \times ( \sin ( i - r )/ cos r)](https://tex.z-dn.net/?f=%20t%20%5Ctimes%20%28%20%5Csin%20%28%20i%20-%20r%20%29%2F%20cos%20r%29)
n = sin i / sin r
sin r = sin 60 / 1.5
sin r = 0.5773
r =
0.5773 = 35.26
d = 0.1 × { sin (60-35.26) / cos 35.2}
= 0.051 m.