a piece of metal having the form of a quadrant of a circle is rolled up so as to form a conical vessel find its contents .when the radius of a quadrant is 10 cm
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we have to find the volume of that cone .
We know that vol. of cone is 1/3(pie x r^2 x h)
so here , h = r
now so vol. = 1/3(pie x 1000) cm^3
1/8×4/3×22/7×100
11/21×100
1100/21cm³
volume of conical vessel =1100/21cm³
if its radius remains same then
1/3×22/7×10×10×h=1100/21
100h=50
h=1/2
hope it helped ,if really yes then please mark as brainliest
and if its wrong then really sorry dear