[tex]according \: to \: pythogras[/tex]
H² = B²+P²
H² = 64 + 225
H² = √289
H = 17
OR I AM SENDING PYTHOGORAS' SOUL TO U
Answer: Given -
Distance Travelled in North - 8km
Distance travelled in East - 15 km
Step-by-step explanation:
So the base in triangle be 8km
And height is 15 km
so By Pythagoras Theorm
([tex]A^{2}[/tex]) + ([tex]B^{2}[/tex]) = [tex]H^{2}[/tex]
[tex]15^{2}[/tex] + [tex]8^{2}[/tex] = [tex]H^{2}[/tex]
225 + 64 =[tex]H^{2}[/tex]
289 = [tex]H^{2}[/tex]
H= [tex]\sqrt{289}[/tex]
Therefore the he is 17 km far from starting point
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Verified answer
[tex]according \: to \: pythogras[/tex]
H² = B²+P²
H² = 64 + 225
H² = √289
H = 17
MARK BRAINLIEST
OR I AM SENDING PYTHOGORAS' SOUL TO U
Answer: Given -
Distance Travelled in North - 8km
Distance travelled in East - 15 km
Step-by-step explanation:
So the base in triangle be 8km
And height is 15 km
so By Pythagoras Theorm
([tex]A^{2}[/tex]) + ([tex]B^{2}[/tex]) = [tex]H^{2}[/tex]
[tex]15^{2}[/tex] + [tex]8^{2}[/tex] = [tex]H^{2}[/tex]
225 + 64 =[tex]H^{2}[/tex]
289 = [tex]H^{2}[/tex]
H= [tex]\sqrt{289}[/tex]
H = 17
Therefore the he is 17 km far from starting point