To divide (2x^3 - 6yx^2 + 12x) m² of land equally among 2x sons, you can simply divide the total land area by the number of sons (2x). Each son will receive:
Land per son = (2x^3 - 6yx^2 + 12x) m² / 2x
Now, let's simplify this expression:
Land per son = (x^2(2x^2 - 6y + 12)) m² / 2x
Land per son = (x^2(2(x^2 - 3y + 6))) m² / 2x
Now, cancel out the common factor of 2x from the numerator and denominator:
Land per son = (x^2(x^2 - 3y + 6)) m² / x
So, each son will receive (x^2 - 3y + 6) m² of land.
Answers & Comments
Answer:
To divide (2x^3 - 6yx^2 + 12x) m² of land equally among 2x sons, you can simply divide the total land area by the number of sons (2x). Each son will receive:
Land per son = (2x^3 - 6yx^2 + 12x) m² / 2x
Now, let's simplify this expression:
Land per son = (x^2(2x^2 - 6y + 12)) m² / 2x
Land per son = (x^2(2(x^2 - 3y + 6))) m² / 2x
Now, cancel out the common factor of 2x from the numerator and denominator:
Land per son = (x^2(x^2 - 3y + 6)) m² / x
So, each son will receive (x^2 - 3y + 6) m² of land.
Step-by-step explanation: