A particle is moving with constant speed in a circular path. When the particle turns by an angle 90° , the ratio of instantaneous velocity to its average velocity is π: x√2 The value of x will be - (1) 7 (2) 2 (3) 1 (4) 5
A particle is moving with a constant speed in a circular path. Find the ratio of average velocity to its instantaneous velocity when the particle describes an angle θ=(
2
Correct option is C)
Let the particle is moving with constant speed v and it reaches the point B in time t
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A particle is moving with a constant speed in a circular path. Find the ratio of average velocity to its instantaneous velocity when the particle describes an angle θ=(
2
Correct option is C)
Let the particle is moving with constant speed v and it reaches the point B in time t
∴ Displacement D=AB=
2
r
Average velocity v
avg
=
t
D
=
t
2
r
..........(1)
Using S=wt+
2
1
αt
2
; where α=0
∴
2
π
=
r
vt
⟹v=
2t
πr
...............(2)
Dividing (1) and (2) we get
v
v
avg
=
πr/2t
2
r/t
=
π
2
2
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