Answer:

Take ground as zero displacement. Consider upward y direction and upward velocity as positive the down ward velocity as negative. g,the acceleration is negative and constant. So acceleration -time graph will be a straight line parallel to t axis and below t axis.

At t=0, position is h. As time during fall increases the position coordinate decreases according to y=h-ut-1/2gt^2 till y becomes zero. From then onward y increases according to y=ut-1/2gt^2..

Velocity v =-gt while falling and v= u-gt while going up . You may take different values of t and find corresponding y and v and draw the graphs of y-t and v-t.

Explanation:

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Answer:

u=50m/s

g=−10m/s

2

The velocity at the highest point will be zero

Thus, v=0

Height can be calculated as,

v

2

−u

2

=2gs

0−2500=−20s

s=125m

Time can be calculated as,

v=u+gt

0=50+(−10)t

t=5sec