Step-by-step explanation:
Given: PQRS is a rectangle, the perpendicular ST from S on PR divides angle S in the ratio 2 : 3.
To find: Here we have to find the value of the angle TPQ.
∠ PSR = 90°
It is given that, the perpendicular ST from S on PR divides angle S in the ratio 2 : 3
Divide the 90° angle into the ratio 2 : 3.
2x+3x=90°
5x = 90°
Therefore,x=18°
2x= 2*18=36°
3x=3*18=54°
So,
∠ PST = 36
Now, in ∠†PST;
∠ PST +∠ PTS +∠ TPS = 180° (Sum of all angles of a triangle)
36° + 90°+ ∠ TPS = 180°
∠ TPS = 180° -36° -90°
∠ TPS = 54°
Now,
∠ TPQ = ∠ SPQ ∠ TPS
∠ TPQ = 90° -54°
∠ TPQ = 36°
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Verified answer
Step-by-step explanation:
Given: PQRS is a rectangle, the perpendicular ST from S on PR divides angle S in the ratio 2 : 3.
To find: Here we have to find the value of the angle TPQ.
∠ PSR = 90°
It is given that, the perpendicular ST from S on PR divides angle S in the ratio 2 : 3
Divide the 90° angle into the ratio 2 : 3.
2x+3x=90°
5x = 90°
Therefore,x=18°
2x= 2*18=36°
3x=3*18=54°
So,
∠ PST = 36
Now, in ∠†PST;
∠ PST +∠ PTS +∠ TPS = 180° (Sum of all angles of a triangle)
36° + 90°+ ∠ TPS = 180°
∠ TPS = 180° -36° -90°
∠ TPS = 54°
Now,
∠ TPQ = ∠ SPQ ∠ TPS
∠ TPQ = 90° -54°
∠ TPQ = 36°
Please mention the second question clearly so that I will be able to answer it
Please mark me as brainliest