Answer:

let the number is 10x+y

here, x+y=9

=> x=9-y

again, 10x+y-27=10y+x

=> 10x+y-10y-x=27

=> 9x-9y=27

=> 9(x-y)=27

=> x-y=27/9=3

=> 9-y-y=3

=> -2y=3-9

=> -2y= -6

=> y= -6/-2

=> y= 3

so,x=9-3=6

the number is 10*6+3=63

Answer:

63

let ones digit be x and tens is 10y

according to question:

x + 10y = 9 ( equation- 1)

after reversed:

10x + y - 27 = x + 10y

10x + y = 9 + 27

10 x + y = 36( equation 2)

From equation 1 2 we get

x + 10y = 9

10x + y = 36

multiply equation 1 by 10 we get

10x + 100y = 90

10x + y = 36

Subtract equation 2 from 1 we get