A monkey climbs 30 feet at the begining of each hour and rests for awhile when he slips back 20 feet before he again starts climbing in the begining of the next hour. If he begins his ascent at 8.00 am ., at what time will he first touch a flag at 120 feet from the ground?
Answers & Comments
Answer:
Explanation Option [c] is correct. From the information given in the question it is clear that the monkey climbs 30 feet and slips 20 feet in each hour, thus he actually climbs 30−20=10 feet in an hour. Thus, he will climb 90 feet in 9 hours and rest 30 feet in 1 hour, i.e., 9 hours + 1 hour = 10 hours.