a man walks (2a - b) km dur north from a fixed point O and then walks a distance (3a + 2b) km due South. What is his final position with respect to O ? ( A kind request to my brothers and sisters following me also )(Fully explained) please this is too urgent
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Verified answer
Step-by-step explanation:
Total displacement in North= Distance travelled North - distance travelled south
= 2a - b - (3a+2b)
= 2a -b -3a - 2b
= -a - 3b
= -(a+3b)
-ve sign shows that net displacement is in south direction... So, his final position is a+3b km due South.
Answer:
R.E.F image
On walking north, he reaches (2a−b) units due north to A.
He moves 3a+2b due south from A.
So, subtract 3a+2b from 2a−b.
∴2a−b−3a−2b=−a−3b
∴ He is (a+3b) distance due south of O.
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