The correct answer is 90°.
Given: Refractive index of glass surface = [tex]\sqrt{3}[/tex].
Angle of incidence = 60°.
To Find: Angle between the refracted and reflected rays.
Solution:
As we know Snell's law.
[tex]u_{1} sin i=u_{2} sinr[/tex]
Here [tex]u_{1}[/tex] is refractive index of air = 1
[tex]u_{2}[/tex] is refractive index of glass surface = [tex]\sqrt{3}[/tex]
∡ i is angle if incidence = 60°
∡ r is angle of refraction = r
By Snell's law
[tex]1sin60=\sqrt{3}sinr\\ \frac{\sqrt{3} }{2} =\sqrt{3} sinr\\ sinr=\frac{1}{2}[/tex]
r = 30°.
Hence, the angle between refracted and reflected ray is 90°.
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Verified answer
The correct answer is 90°.
Given: Refractive index of glass surface = [tex]\sqrt{3}[/tex].
Angle of incidence = 60°.
To Find: Angle between the refracted and reflected rays.
Solution:
As we know Snell's law.
[tex]u_{1} sin i=u_{2} sinr[/tex]
Here [tex]u_{1}[/tex] is refractive index of air = 1
[tex]u_{2}[/tex] is refractive index of glass surface = [tex]\sqrt{3}[/tex]
∡ i is angle if incidence = 60°
∡ r is angle of refraction = r
By Snell's law
[tex]1sin60=\sqrt{3}sinr\\ \frac{\sqrt{3} }{2} =\sqrt{3} sinr\\ sinr=\frac{1}{2}[/tex]
r = 30°.
Hence, the angle between refracted and reflected ray is 90°.
#SPJ1