A ladder placed against such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle 60 degree. Find how far the ladder is from the foot of the wall.
1. Write a paragraph explaining how far is the ladder is from the foot of the wall.
2. Determine the other trigonometric ratios.
3. What learning have you discovered in doing such activity? Would you be able to use this in your life? How and why?
[ I need a serious answer, please. Thank you. ]
1. Write a paragraph explaining how far is the ladder is from the foot of the wall.
2. Determine the other trigonometric ratios.
3. What learning have you discovered in doing such activity? Would you be able to use this in your life? How and why?
[ I need a serious answer, please. Thank you. ]
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Answer:
AB=height
BC=base
AC=ladder
now
<C=60°
now
tan 60=opposite/hypotenuse
√3=6/BC
BC=6√3/3
BC=2√3 or 3.46m
ladder is 2√3 or 3.46m farfrom the foot of the wall.
AB=Height
BC=Base
AC=Ladder
Now :
<C=60°
Now :
Tan 60 opposite / hypotenuse
√3=6 / BC
BC=6√3 / 3
BC=2√3 or 3.46m
Ladder is 2√ 3 or 3.46m farfrom the foot of the wall.
#carryonlearning:)