A joker’s cap is in the form of right circular cone whose base radius is 7 cm and height is 24 cm. Find the area of the sheet required to make 10 such caps.
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HELLO DEAR,GIVEN:-
radius of cone r = 7cm
height of cone h = 24cm
slant height l = √(24² + 7²) = √(576 + 49) = √625
l = 25cm
since, joker's cap is in the form of right circular cone
so, area of joker's cap = πrl
=> 22/7 × 7 × 25
=> 22 × 25
=> 550cm²
so, curved surface area of 1 joker's cap = 550cm²
curved surface area 10 joker's cap = 10 × 550 = 5500cm²
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