Radius of the cap = 7cm Height of the cap = 24cm We know that Slant height of the cap l = √(r2 + h2) By substituting the values l = √(72 + 242) On further calculation l = √(49 + 576) = √625 So we get l = 25cm We know that Curved surface area of one cap = πrl By substituting the values Curved surface area of one cap = (22/7) × 7 × 25 So we get Curved surface area of one cap = 550 cm2 So the curved surface area of 10 conical caps = 10 × 550 = 5500 cm2 Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.Read more on Sarthaks.com - https://www.sarthaks.com/721548/jokers-form-right-circular-cone-base-radius-height-24cm-find-area-sheet-required-make-such
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(5500) cm2 is the ans of your q
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Radius of the cap = 7cm Height of the cap = 24cm We know that Slant height of the cap l = √(r2 + h2) By substituting the values l = √(72 + 242) On further calculation l = √(49 + 576) = √625 So we get l = 25cm We know that Curved surface area of one cap = πrl By substituting the values Curved surface area of one cap = (22/7) × 7 × 25 So we get Curved surface area of one cap = 550 cm2 So the curved surface area of 10 conical caps = 10 × 550 = 5500 cm2 Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.Read more on Sarthaks.com - https://www.sarthaks.com/721548/jokers-form-right-circular-cone-base-radius-height-24cm-find-area-sheet-required-make-such